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4m^2-17m-10=0
a = 4; b = -17; c = -10;
Δ = b2-4ac
Δ = -172-4·4·(-10)
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{449}}{2*4}=\frac{17-\sqrt{449}}{8} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{449}}{2*4}=\frac{17+\sqrt{449}}{8} $
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